Quadratic Equations Chapter 4 | Mathematics

Complete NCERT notes, standard form, methods (factorization, completing square, quadratic formula), discriminant, nature of roots, word problems, and key points for CBSE Class 10 Board Exam 2025-26.

📖 Introduction

A quadratic equation is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers and a ≠ 0.

The term "quadratic" comes from "quadratum" (Latin for square) because the variable gets squared. These equations arise in many real-life situations: projectile motion, area problems, profit maximization, etc.

📌 Standard Quadratic Equation

ax² + bx + c = 0, a ≠ 0
📐 Standard Form of Quadratic Equation

General form: ax² + bx + c = 0

✅ Examples

2x² + 3x - 5 = 0 → a=2, b=3, c=-5
x² - 4x = 0 → a=1, b=-4, c=0
3x² + 2 = 0 → a=3, b=0, c=2
💡 If a = 0, the equation becomes linear (bx + c = 0), not quadratic.
✖️ Factorization Method (Splitting the Middle Term)

Steps:

📝 Example

Solve: x² - 5x + 6 = 0
ac = 6, b = -5 → numbers -2 and -3 (product 6, sum -5)
x² - 2x - 3x + 6 = 0 → x(x-2) -3(x-2)=0 → (x-2)(x-3)=0
→ x = 2 or x = 3
🔲 Completing the Square Method

Steps:

📝 Example

Solve: x² + 4x - 5 = 0
x² + 4x = 5
Add (4/2)² = 4 to both sides: x² + 4x + 4 = 9
(x + 2)² = 9 → x + 2 = ±3 → x = 1 or x = -5
📏 Quadratic Formula (Sridharacharya Formula)

📌 The Formula

x = [-b ± √(b² - 4ac)] / 2a

This formula gives the roots of any quadratic equation ax² + bx + c = 0, a ≠ 0.

📝 Example

Solve: 2x² - 7x + 3 = 0
a=2, b=-7, c=3
x = [7 ± √(49 - 24)] / 4 = [7 ± √25]/4 = [7 ± 5]/4
x = 12/4 = 3 or x = 2/4 = 0.5
🎯 Discriminant (D)

📌 Definition

D = b² - 4ac

The discriminant determines the nature of the roots without solving the equation.

🌱 Nature of Roots
Discriminant (D)Nature of Roots
D > 0Two distinct real roots
D = 0Two equal real roots (one repeated root)
D < 0No real roots (complex roots, not in Class 10)
💡 Additional: If D is a perfect square, roots are rational; otherwise, they are irrational.

📝 Sum and Product of Roots

For ax² + bx + c = 0,
Sum of roots (α+β) = -b/a
Product of roots (αβ) = c/a
📐 All Important Formulas

1️⃣ Quadratic Formula

x = [-b ± √(b²-4ac)]/2a

2️⃣ Discriminant

D = b² - 4ac

3️⃣ Sum of Roots

α + β = -b/a

4️⃣ Product of Roots

αβ = c/a

5️⃣ Forming Quadratic

x² - (α+β)x + αβ = 0

6️⃣ (α-β)²

(α-β)² = (α+β)² - 4αβ = (b²-4ac)/a²
📝 NCERT Solved Examples (In-depth)

Example 1: Factorization Method

Solve: 2x² - 5x + 3 = 0
ac = 6, b = -5 → numbers -2 and -3
2x² - 2x - 3x + 3 = 0 → 2x(x-1) -3(x-1)=0 → (x-1)(2x-3)=0
→ x = 1 or x = 3/2

Example 2: Completing the Square

Solve: 4x² + 4√3x + 3 = 0
Divide by 4: x² + √3x + 3/4 = 0 → x² + √3x = -3/4
Add (√3/2)² = 3/4: x² + √3x + 3/4 = 0 → (x + √3/2)² = 0 → x = -√3/2 (repeated root)

Example 3: Quadratic Formula

Solve: 3x² - 2√6x + 2 = 0
a=3, b=-2√6, c=2
D = (-2√6)² - 4×3×2 = 24 - 24 = 0
x = (2√6 ± 0)/(6) = √6/3 (repeated root)

Example 4: Word Problem (Area)

The area of a rectangular plot is 528 m². Length is one more than twice its breadth. Find length and breadth.
Let breadth = x m, length = (2x+1) m
x(2x+1) = 528 → 2x² + x - 528 = 0
D = 1 + 4224 = 4225 = 65²
x = (-1 ± 65)/4 → x = 64/4=16 or x = -66/4 (reject)
Breadth = 16 m, Length = 33 m

Example 5: Nature of Roots

Find k so that 2x² + kx + 3 = 0 has equal roots.
For equal roots, D = 0 → k² - 4×2×3 = 0 → k² - 24 = 0 → k = ±√24 = ±2√6
Key Points for Board Exam (Deep Research)

📌 Quick Reference Card

MethodWhen to UseKey Step
FactorizationSimple middle term splittingac = product, sum = b
Completing SquareLeading coefficient = 1, even bAdd (b/2)² to both sides
Quadratic FormulaAlways worksDirect substitution

📌 Important Identities for Word Problems

Consecutive numbers: x, x+1, x+2
Area of rectangle: length × breadth
Speed = Distance / Time → Time = Distance/Speed
Product of two numbers = constant → one = k/x
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